..............................
your code
// display array with for loop
for (int i = 0; i < 8; i++){
cout << "The word is " << letters [i] << " => " << letters[i] << endl;
}
prints this
the word is [letter1] => [letter1]
the word is [letter2] => [letter2]
....
i asume you want something like this
the word is [letter1 letter2 ... letter8 ] ...
to do that you want to print "the word is " outside the for loop
then inside
for (int i = 0; i < 8; i++){
cout << letters[i];
}
this will just print the letters after each one
finally print out the endln to move onto the next line
to print backwards it you have to start your i at 7, then make sure i is greater then zero while you decrement with i--
then print your letters with letters[i]
I am stuck on looping out the array of the user input in the form of a single word, instead of displaying each letter individually from the array. Also I am unsure on how to display the reverse of the word, help would be greatly appreciated!
I have to meet the following 4 steps:
1. Create an array to store 8 characters.
2. Using a for loop, get an 8-letter word from the user, one letter at a time.
3. Then use another for loop to print the complete word onto the screen one letter at a time.
4. Then use a third for loop to print out the word backwards.
Currently my code looks like :
#include
using namespace std;
int main()
{
// array
char letters[8];
char eletter[] = "Please enter a letter: ";
// fill array
for (int i = 0; i < 8; i++){
cout << eletter;
cin >> letters[i];
}
cout << endl;
// display array with for loop
for (int i = 0; i < 8; i++){
cout << "The word is " << letters [i] << " => " << letters[i] << endl;
}
cout << endl;
for (int i = 0; i < 8; i--){
cout << "The word backwards is " << i << endl;
}
system("PAUSE");
}
