If you wan to calculate fractional Part ,Why you are entering "quit" .
If you want integer input during execution use nextInt in place of nextLine
e.g.
Scanner sc = new Scanner(System.in);
int i = sc.nextInt();
2) The parseInt converts string input to the integer one which is like this
int i=Integer.parseInt("123"); //then i become 123
i=i+1;
System.out.println(i); // output will be 124
Comment if any other issue
Syntax:
All the variant of this method are given below:
static int parseInt(String s)
static int parseInt(String s, int radix)
Parameters:
Here is the detail of parameters:
s -- This is a string representation of decimal.
radix -- This would be used to convert String s into integer.
So I have the following program:
public class fractionalCalculator {
public static void main(String[] args) {
Scanner sc = new Scanner (System.in);
boolean x = true;
while (x == true) {
System.out.print("Enter an expression:");
String userInput = sc.nextLine();
System.out.println(userInput);
if (userInput.equals ("quit")) {
sc.close();
System.out.println("Come back soon!");
x = false;
}
}
}
}
---
With the program, we are supposed to turn the userInput into an integer when able to. However, I am having trouble how to apply parseInt. Can it be like int userInput = Integer.parseInt(//here I don't know what to put);
The overall desired result would be the output saying what is the numerator and what is the denominator (which for now should be 1 or -1 since the only input currently should be integer numbers)
My thoughts tell me that I should be using another if loop that says if userInput = int, but I do not know.
