//get the starting integer from the user
int starter = getUserInput();
//start the for loop
for (int x = starter; x > 0; x--) {
//need a separate condition for 0 since it needs to print 'none'
if (x == 0) {
print "There is none.";
} else {
print "There is " + x + ".";
}
}
That should get it done.
Language? In Python 2, you could have something like this:
#!/usr/bin/python
number = int(input("Enter a number in the range 2 - 10: "))
i = number
while i>=0:
.... if i>0:
.... .... print "There is",i
.... else:
.... .... print "There is none"
.... i -= 1
#Note: I've used "...." to represent tabs, which Y!Answers removes.
The same code but this time in Java:
import java.util.Scanner;
public class CountingDown {
public static void main(String[] args) {
Scanner in = new Scanner(System.in);
System.out.print("Enter a number between 2 and 10: ");
int number = in.nextInt();
int i = number;
while (i>=0) {
if (i>0) {
System.out.println("There is "+i);
} else {
System.out.println("There is none");
} // end if
i--;
} // end while
} // end main()
} // end class CountingDown
either one, both will work.
cin>>number;
for (int i = number, i > 0, i--) cout<<"There is "<
cout<<"There is none";
A for loop is good for when you want your program to loop a given number of times. In this case, the given number is the inputted number.
For example, I need a range of 2 - 10.
I ask a user to enter a number in that range.
User enters 3
The output should like this:
There is 3
There is 2
There is 1
There is none
What do i do?
