Did you write the code that produced the table above? If so, show us the code.
Edit:
Replace sum = sum + number; with:
sum += number; // does the same thing as your statement
sum2 += square;
sum3 += cube;
Note: A picture of code is NOT code. In the future, if someone asks for code, you should supply the actual text so they can run it. You can use a code-posting site such as ideone.com or codepad.org and then paste the link here.
You could also calculate cube with:
cube = square * number;
You can use following code for it
int n,i;
n=10;
for(i=1;i<=n;i++)
{
printf("%d %d %d",i,i*i,i*i*i);
}
here is the code
Try:
#include
int main( void ) {
? ? int i, sum, sum2, sum3;
? ? sum= sum2= sum3= 0;
? ? printf( "\tNumber\tSquares\tCube\n" );
? ? for ( i= 1; i <= 10; ++i ) {
? ? ? ? printf( "\t%-6d\t%-6d\t%-6d\n", i, i*i, i*i*i );
? ? ? ? sum += i, sum2 += i*i, sum3 += i*i*i;
? ? }
? ? for ( i= 0; i < 48; ++i ) putchar( '-' );
? ? printf( "\nSum:\t%-6d\t%-6d\t%-6d\n", sum, sum2, sum3 );
? ? return 0;
}
How to add all number after square them and print in C programming (For loop case)
