>(define RectangleArea_squaremiles
(lambda (east-west_yards north-south_furlongs)
(* (/ east-west_yards 1760) (/ north-south_furlongs 8))))
>(RectangleArea_squaremiles 3520 40)
>(RectangleArea_squaremiles 17600 80)
; 3. Call within Function
>(define TriangleArea_squaremiles
(lambda (east-west_yards north-south_furlongs)
(/ (RectangleArea_squaremiles east-west_yards north-south_furlongs) 2)))
How does using "(RectangleArea_squaremiles east-west_yards north-south_furlongs)" help? What is happening there?
How would I create a function named SquareArea_squaremiles with parameter side_yards using RectangleArea_squaremiles
a furlong is 220 yards.
1,760 yards in a mile.
8 furlongs in a mile.
