Source:
public class Example {
public static void main(String[] args) {
System.out.println("/\'\\\'\'/\'\\");
}
}
Output:
$ java Example
/'\''/'\
In a string literal, you need to precede each special character with a backslash if you want to output it as is. Your string contains two special characters: the backslash and the double quote. So you need to tell Java to print "/’\\\"/'\\".
System.out.println("/'\\''/'\\");
I'm assuming that the '' part of the string is two single quotes next to each other (as you specified in the question), not a double quote.
how would i write a an output statement which will output the following characters exactly as shown: /'\''/'\
