wrong_number = 7
i = wrong_number
while (i==wrong_number):
...print "Enter any number except" , wrong_number
...i = int(raw_input())
...if i==wrong_number:
... ... print "Try again."
print "The number you entered was", i
# Note: tabs are represented by "..."
Thanks for the help. I also figured this:
A=input("question")
If a is t:
print "try again"
else:
print " OK, loading for ", a, "."
Here you go:
http://ideone.com/AXRch0
I am creating a program with Python where the user is asked to type an input, but they are told not to put 7. Even thought I tell them not to, the user can still put 7. How do I get the computer to say "try again" if the user types 7?
