int x=180; double y;

printf("output =%d \n ",sqrt(25)+10);

output is 0

and here also zero

printf("result %f \n",abs(-5.67)+15);

output is 0.000000

sqrt() returns a float you are trying to print it as an int

abs returns an int you are trying to print it as a float (double really due to default argument promotion)

#include

int main(void){

int x=180; double y;

printf("output =%d \n ",(int) sqrt(25)+10);

printf("output =%f \n ", sqrt(25)+10);

printf("result %d \n", abs((int)-5.67)+15);

return 0;

}

or you can

#include

for the prototype for abs()

the compiler does not know what arguments abs() takes

you are giving it a float so it assumes that is right

but abs() really takes an int --- oops.

so you can #include for the prototype

add it yourself (not recommended)

int abs(int);

or cast the argument to int

abs((int) -5.7)

[ C does not have ANY "commands" - it has keywords, functions, labels, statements and expressions -- no "commands"]

int x=180; double y;

printf("output =%d \n ",sqrt(25)+10);

output is 0

and here also zero

printf("result %f \n",abs(-5.67)+15);

output is 0.000000