f(x) = (e^x)/(1+e^-x)
is 0. How do you find this? I know how to do it x is the base, but how if it is in the exponent?
I see that the horizontal asymptotes of
f(x) = (e^x)/(1+e^-x)
is 0. How do you find this? I know how to do it x is the base, but how if it is in the exponent?
